X^2-50x-840=0

Solution for X^2-50x-840=0 equation:

X^2-50X-840=0

a = 1; b = -50; c = -840;
Δ = b2-4ac
Δ = -502-4·1·(-840)
Δ = 5860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5860}=\sqrt{4*1465}=\sqrt{4}*\sqrt{1465}=2\sqrt{1465}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{1465}}{2*1}=\frac{50-2\sqrt{1465}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{1465}}{2*1}=\frac{50+2\sqrt{1465}}{2}
$